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14n^2+34n-24=0
a = 14; b = 34; c = -24;
Δ = b2-4ac
Δ = 342-4·14·(-24)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-50}{2*14}=\frac{-84}{28} =-3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+50}{2*14}=\frac{16}{28} =4/7 $
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